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| Time Limit: 2000MS | Memory Limit: 65536K | |
| Total Submissions: 27698 | Accepted: 11148 |
Description
Input
Output
Sample Input
3 3 1 2 2 1 2 3
Sample Output
1
Hint
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<vector>
#include<stack>
#define MAX 50010
#define INF 0x3f3f3f
using namespace std;
struct node
{
int beg,end,next;
}edge[MAX];
int low[MAX],dfn[MAX];
int n,m,ans;
int sccno[MAX],instack[MAX];
int dfsclock,scccnt;
vector<int>newmap[MAX];
vector<int>scc[MAX];
int head[MAX];
int out[MAX];
stack<int>s;
int sum,sumout,ant;
void init()
{
ans=0;
memset(head,-1,sizeof(head));
}
void add(int u,int v)
{
edge[ans].beg=u;
edge[ans].end=v;
edge[ans].next=head[u];
head[u]=ans++;
}
void getmap()
{
int a,b,i;
while(m--)
{
scanf("%d%d",&a,&b);
add(a,b);
}
}
void tarjan(int u)
{
int v,i,j;
s.push(u);
instack[u]=1;
dfn[u]=low[u]=++dfsclock;
for(i=head[u];i!=-1;i=edge[i].next)
{
v=edge[i].end;
if(!dfn[v])
{
tarjan(v);
low[u]=min(low[u],low[v]);
}
else if(instack[v])
low[u]=min(low[u],dfn[v]);
}
if(dfn[u]==low[u])
{
scccnt++;
while(1)
{
v=s.top();
s.pop();
instack[v]=0;
sccno[v]=scccnt;
if(v==u)
break;
}
}
}
void find(int l,int r)
{
memset(low,0,sizeof(low));
memset(dfn,0,sizeof(dfn));
memset(instack,0,sizeof(instack));
memset(sccno,0,sizeof(sccno));
dfsclock=scccnt=0;
for(int i=l;i<=r;i++)
{
if(!dfn[i])
tarjan(i);
}
}
void suodian()
{
int i;
ant=0;
for(i=1;i<=scccnt;i++)
{
newmap[i].clear();
out[i]=0;
}
for(i=0;i<ans;i++)
{
int u=sccno[edge[i].beg];
int v=sccno[edge[i].end];
if(u!=v)
{
newmap[u].push_back(v);
out[u]++;
}
}
}
void solve()
{
int i,j;
sumout=0;sum=0;
for(i=1;i<=scccnt;i++)
{
if(!out[i])
{
sumout++;
ant=i;
}
}
if(sumout==0)
{
printf("%d\n",n);
return ;
}
else if(sumout==1)
{
for(i=1;i<=n;i++)
if(sccno[i]==ant)
sum++;
printf("%d\n",sum);
}
else
printf("0\n");
}
int main()
{
int t;
while(scanf("%d%d",&n,&m)!=EOF)
{
init();
getmap();
find(1,n);
suodian();
solve();
}
return 0;
}
poj 2186 Popular Cows【tarjan求scc个数&&缩点】【求一个图中可以到达其余所有任意点的点的个数】
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原文地址:http://www.cnblogs.com/tonghao/p/4823588.html