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Invert a binary tree.
4 / 2 7 / \ / 1 3 6 9
to
4 / 7 2 / \ / 9 6 3 1
Trivia:
This problem was inspired by this original tweet by Max Howell:
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
置换,用递归,左右子树置换
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode invertTree(TreeNode root) { if(root == null) return root; else { if(root.left!=null && root.right!=null) { TreeNode temp; temp = root.left; root.left = root.right; root.right = temp; invertTree(root.left); invertTree(root.right); } else if(root.left == null && root.right !=null) { root.left = root.right; root.right = null; invertTree(root.left); } else if(root.left != null && root.right ==null) { root.right = root.left; root.left = null; invertTree(root.right); } else { return root; } } return root; } }
leetcode 226: Invert Binary Tree
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原文地址:http://www.cnblogs.com/cactus1504/p/4823790.html