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leetcode 283:Move Zeroes

时间:2015-09-20 19:16:09      阅读:156      评论:0      收藏:0      [点我收藏+]

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题目:

Given an array nums, write a function to move all 0‘s to the end of it while maintaining the relative order of the non-zero elements.

For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].

Note:

You must do this in-place without making a copy of the array.
Minimize the total number of operations.

思路:

算法时间复杂度 最坏为n2,感觉可以为n,类似于快排(二次的时候,考虑优化

代码:

public class Solution {
    public void moveZeroes(int[] nums) {
        int flag =0, count = 0;
        for(int i=0; i<nums.length-1; i++) {        
            if(nums[i] == 0) {
                for(int j=i+1; j<nums.length; j++) {
                    flag = 0;
                    if(nums[j] != 0) {
                        nums[i] = nums[j];
                        nums[j] = 0;
                        flag = 1;
                        count ++;
                        break;
                    }
                }
            }
            if(flag ==0 && count>0)
                break;
        }
    }
}

 

leetcode 283:Move Zeroes

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原文地址:http://www.cnblogs.com/cactus1504/p/4823918.html

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