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1 题目：
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 → 1[1,3,5,6], 7 → 4[1,3,5,6], 0 → 0
2 思路：
变相的二分搜索
注意处理边界和溢出情况
3 代码：
public int searchInsert(int[] nums, int target) { // pre handle if(nums[0] > target){ return 0; } if(nums[nums.length-1] < target){ return nums.length; } /* again, binary search */ int pre = 0; int after = nums.length-1; while(pre<=after){ int mid = pre + ((after-pre)>>1); if(nums[mid]==target){ return mid; }else if(nums[mid]<target){ if(mid < nums.length-1 && nums[mid+1]>target){ return mid+1; } pre = mid+1; }else if (nums[mid]>target){ if(mid>0 && nums[mid-1]<target){ return mid; } after = mid-1; } } // will never reach here return 0; }
[leetcode 35] Search Insert Position
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原文地址：http://www.cnblogs.com/lingtingvfengsheng/p/4827532.html
