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#include <stdio.h>
int MaxSub(int A[],int N){
return MaxSubSeq(A,0, N-1);
}
int Max3(int x, int y, int z){
if(x > y){
if(x > z){
return x;
}
else{
return z;
}
}
else{
if(y > z){
return y;
}
else{
return z;
}
}
}
int MaxSubSeq(int A[],int Left,int Right){
int MaxLeftSum,MaxRightSum;
int MaxLeftBorderSum,MaxRightBorderSum;
int LeftBorderSum,RightBorderSum;
if(Left == Right){
if(A[Left] > 0){
return A[Left];
}
else
return 0;
}
int Mid = (Left + Right)/2;
MaxLeftSum = MaxSubSeq(A,Left,Mid);
MaxRightSum = MaxSubSeq(A,Mid+1, Right);
MaxLeftBorderSum = 0;LeftBorderSum = 0;
int i;
for(i = Mid; i >= Left ; i--){
LeftBorderSum += A[i];
if(LeftBorderSum > MaxLeftBorderSum){
MaxLeftBorderSum = LeftBorderSum;
}
}
MaxRightBorderSum = 0; RightBorderSum = 0;
for(i = Mid+1; i<= Right; i++){
RightBorderSum += A[i];
if(RightBorderSum > MaxRightBorderSum){
MaxRightBorderSum = RightBorderSum;
}
}
return Max3(MaxLeftSum,MaxRightSum, (MaxLeftBorderSum + MaxRightBorderSum));
}
int main(){
int K;
int i;
scanf("%d",&K);
int Arr[K];
for(i = 0 ; i< K; i++){
scanf("%d",&Arr[i]);
}
printf("%d",MaxSub(Arr,K));
return 0;
}
给定K个整数组成的序列{ N?1??, N?2??, ..., N?K?? },“连续子列”被定义为{ N?i??, N?i+1??, ..., N?j?? },其中 1≤i≤j≤K。“最大子列和”则被定义为所有连续子列元素的和中最大者。例如给定序列{ -2, 11, -4, 13, -5, -2 },其连续子列{ 11, -4, 13 }有最大的和20。现要求你编写程序,计算给定整数序列的最大子列和。
输入第1行给出正整数K (≤100000);第2行给出K个整数,其间以空格分隔。
在一行中输出最大子列和。如果序列中所有整数皆为负数,则输出0。
6
-2 11 -4 13 -5 -2
20标签:
原文地址:http://www.cnblogs.com/yangRyoung/p/4830178.html