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链接:
http://poj.org/problem?id=2406
Description
Input
Output
Sample Input
abcd aaaa ababab .
Sample Output
1 4 3
Hint
#include<stdio.h> #include<string.h> #include<stdlib.h> #define N 1000007 char S[N]; int Next[N]; /// Next中存的是前缀和后缀的最大相似度 void FindNext(int Slen, int Next[]) ///Next[i] 代表前 i 个字符的最大匹配度 { int i=0, j=-1; Next[0] = -1; while(i<Slen) { if(j==-1 || S[i]==S[j]) Next[++i] = ++j; else j = Next[j]; } } int main() { while(scanf("%s", S), strcmp(S, ".")) { int Slen=strlen(S); FindNext(Slen, Next); if(Slen%(Slen-Next[Slen])) printf("1\n"); else printf("%d\n", Slen/(Slen-Next[Slen])); } return 0; }
(求循环节的个数)Power Strings -- poj -- 2406
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原文地址:http://www.cnblogs.com/YY56/p/4833391.html