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第二次作业(个人项目实践)

时间:2015-09-23 23:16:29      阅读:279      评论:0      收藏:0      [点我收藏+]

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1.设计一个A类,实现对一维数组的指定范围内的元素的相加运算

源代码:

 1 package s001;
 2 import java.util.Scanner;
 3 public class A {
 4 
 5     
 6     public static int count(int[]arr,int start,int end,int sum){
 7         
 8         
 9         for(int i=start;i<=end;i++)
10             sum+=arr[i];
11         return sum;
12     }
13     public static void main(String[] args) {
14         
15        int s=0; 
16        
17        int []a=new int[]{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}; 
18       
19     Scanner sc=new Scanner(System.in);
20       System.out.println("请依次输入m、n:");
21        int m= sc.nextInt(); 
22        int n=sc.nextInt();
23          System.out.println("m为:" +m);
24           System.out.println("n为:" +n);
25        
26        A.count(a,m,n,s );
27       
28       System.out.println("sum="+A.count(a, m, n, s));
29     }
30 }

A测试:

技术分享

验证:

技术分享

2.设计一个B类,实现对二维数组内指定范围内元素的相加运算

 1 package s001;
 2 import java.util.Scanner;
 3 
 4 public class B {
 5     
 6   public static int count(int[][]arr,int start1,int start2,int end1,int end2,int sum){
 7       
 8       for(int i=start1;i<=end1;i++)
 9          {
10              for(int j=start2;j<=end2;j++)
11              {
12                  sum+=arr[i][j];
13              }
14          }    
15        return sum;
16             
17     }
18     
19     public static void main(String[] args) {
20         
21          int s=0;
22          int[][] b=new int[][]{{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767},{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}};   
23         
24          Scanner sc = new Scanner(System.in);
25          System.out.println("请输入m1,n1,m2,n2:");
26          
27           int m1 = sc.nextInt();
28           int n1 = sc.nextInt();
29           
30              System.out.println("m1=" +m1);
31              System.out.println("n1=" +n1);
32           
33           int m2 = sc.nextInt();
34           int n2= sc.nextInt();
35           
36              System.out.println("m2=" +m2);
37              System.out.println("n2=" +n2);
38           
39           B.count(b,m1,n1,m2,n2,s );
40              System.out.println("sum="+B.count(b,m1,n1,m2,n2,s ));
41     }     
42 
43 }

B测试:

技术分享

验证:

技术分享

3.设计一个C类,实现对三维数组的指定范围内的元素相加运算

 1 package s001;
 2 import java.util.Scanner;
 3 
 4 public class C {
 5     
 6     public static int count(int[][][]arr,int start1,int end1,int start2,int end2,int start3,int end3,int sum){
 7         
 8         for(int i=start1;i<=end1;i++)
 9          {
10              for(int j=start2;j<=end2;j++)
11              {
12                  for(int k=start3;k<=end3;k++)
13                  {
14                      sum+=arr[i][j][k];
15                                   
16                  }
17                  
18              }
19          }    
20           return sum;
21             
22     }
23     public static void main(String[] args) {
24         
25          int s=0;
26          int[][][] c = new int[][][]{
27            {{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}}, 
28            {{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}},
29            {{302,-7944,-6551,6648,-884,-6332,1188,-248,3902,-2171,-3782,-3510,6203,-636,-4605,4497,3187,-6278,1198,-7963,7647,-3022,-8267,7995,-1998,-4171,730,-8117,-1706,7601,-2454,-6161,-1810,243,-2841,-5377,2985,2328,177,5622,3596,3057,2830,-1151,6566,2254,6972,-3060,4063,367,84,3156,3880,-1530,5272,1385,-565,-1736,1267,-3863,-229,2072,2423,-7449,9555,2844,-1278,-3613,-919,4153,-4232,4032,-5732,199,4792,2498,-3344,-4193,2650,-579,3416,-3575,1822,-6936,-2661,-1873,414,2314,6844,7613,-7844,6680,5974,2208,-3597,6302,4396,-141,-1864,1939}}
30            
31         };
32        Scanner sc= new Scanner(System.in) ;
33          System.out.println("请输入m1,n1,m2,n2,m3,n3:");
34            int m1 = sc.nextInt();
35            int n1 = sc.nextInt();
36               System.out.println("m1=" +m1);
37               System.out.println("n1=" +n1);
38               
39            int m2 = sc.nextInt();
40            int n2= sc.nextInt();
41               System.out.println("m2=" +m2);
42               System.out.println("n2=" +n2);
43               
44            int m3 = sc.nextInt();
45            int n3= sc.nextInt();
46               System.out.println("m3=" +m3);
47               System.out.println("n3=" +n3);
48               
49            C.count(c,m1,n1,m2,n2,m3,n3,s );
50               System.out.println("sum="+C.count(c,m1,n1,m2,n2,m3,n3,s ));
51    }
52   
53     
54 }

C测试:

技术分享

验证:

技术分享

小结:

    最开始做这个题目的时候,没有理解老师的意思,完全跑题了。后来看了班上同学和老师们的聊天记录,才知道自己想偏了。可是还是不知道从何下手,后来参考了一下林杰同学做的,有一点点思路了却还是不怎么明确。后来看到了宝玉老师和鞠老师说的,有了一点点启发。迫于作业截止时间快到了,就先把做的东西发上来,再慢慢改进吧,看到这么繁琐的代码我也是醉了。希望老师可以指导一下

   

第二次作业(个人项目实践)

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原文地址:http://www.cnblogs.com/Ryangmei/p/4833717.html

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