标签:
有向环最小权值覆盖问题
http://blog.csdn.net/u013480600/article/details/39159407
#include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; //设置节点数量 const int maxn=450+10; const int INF=0x7FFFFFFF; struct Edge { int from,to,cap,flow,cost; }; int n,m,len,s,t; vector<Edge> edges; vector<int> G[maxn]; int inq[maxn]; int d[maxn]; int p[maxn]; int a[maxn]; void init() { for(int i=0; i<maxn; i++) G[i].clear(); edges.clear(); } void Addedge(int from,int to,int cap,int cost) { edges.push_back((Edge) { from,to,cap,0,cost }); edges.push_back((Edge) { to,from,0,0,-cost }); len=edges.size(); G[from].push_back(len-2); G[to].push_back(len-1); } bool BellmanFord(int s,int t,int &flow,int &cost) { for(int i=0; i<maxn; i++) d[i]=INF; memset(inq,0,sizeof(inq)); memset(p,-1,sizeof(p)); d[s]=0; inq[s]=1; p[s]=0; a[s]=INF; queue<int>Q; Q.push(s); while(!Q.empty()) { int u=Q.front(); Q.pop(); inq[u]=0; for(int i=0; i<G[u].size(); i++) { Edge& e=edges[G[u][i]]; if(e.cap>e.flow&&d[e.to]>d[u]+e.cost) { d[e.to]=d[u]+e.cost; p[e.to]=G[u][i]; a[e.to]=min(a[u],e.cap-e.flow); if(!inq[e.to]) { Q.push(e.to); inq[e.to]=1; } } } } if(d[t]==INF) return false; flow+=a[t]; cost+=d[t]*a[t]; int u=t; while(u!=s) { edges[p[u]].flow+=a[t]; edges[p[u]^1].flow-=a[t]; u=edges[p[u]].from; } return true; } void Mincost (int s,int t) { int flow=0,cost=0; while(BellmanFord(s,t,flow,cost)); printf("%d\n",cost); } int main() { int T; scanf("%d",&T); while(T--) { scanf("%d%d",&n,&m); init(); s=0; t=2*n+1; for(int i=1; i<=n; i++) Addedge(s,i,1,0); for(int i=1; i<=n; i++) Addedge(i+n,t,1,0); for(int i=1; i<=m; i++) { int u,v,w; scanf("%d%d%d",&u,&v,&w); Addedge(u,v+n,1,w); } Mincost(s,t); } return 0; }
标签:
原文地址:http://www.cnblogs.com/zufezzt/p/4838899.html