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1 题目
Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.
The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘.
A partially filled sudoku which is valid.
Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.
2 思路
开始就以为是完全填完，看最后能不能填出来。
结果题目意思是根据已有的数据，判断是否已经挂了。这也是看完别人的代码才知道的。。
3 代码：
// only need to examin the providing num is Valid int len = board.length; Boolean[][] row = new Boolean[len][len]; Boolean[][] column = new Boolean[len][len]; Boolean[][] sub = new Boolean[len][len]; for (int i = 0; i < sub.length; i++) { Arrays.fill(row[i], false); Arrays.fill(column[i], false); Arrays.fill(sub[i], false); } for(int i=0;i<len;i++){ for(int j=0;j<len;j++){ if(board[i][j] != ‘.‘){ int num = board[i][j] - ‘1‘; int k = i/3*3+j/3; if(row[i][num] || column[j][num] || sub[k][num]){ return false; } row[i][num]=column[j][num]=sub[k][num] = true; } } } return true; }
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原文地址：http://www.cnblogs.com/lingtingvfengsheng/p/4842639.html
