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1 题目:
根据给出的数独,全部填出来
2 思路:
为了做出来,我自己人工做了一遍题目给的数独。思路是看要填的数字横、竖、子是否已经有1-9的数字,有就剔除一个,最后剩下一个的话,就填上。一遍一遍的循环,直到填完为止。
后来发现,这个思路只能解决部分数独。还有部分数独是需要回溯的,比如,这个位置只能填3或5,那么就需要先填上3,看看能否继续填下去,不能的话,再回过来填5。
想了半天,想不出来,把别人的backtracking看懂了,写出来了。。
3 代码:
自己的:
Hashtable<Integer, List<Character>> table; int row; int column; int totalNum; public void solveSudoku(char[][] board) { if (board.length == 0) { return; } row = board.length; column = board[0].length; totalNum = row * column; table = new Hashtable<Integer, List<Character>>(totalNum); for (int i = 0; i < row; i++) { for (int j = 0; j < column; j++) { if (board[i][j] == ‘.‘) { List<Character> validNum = new ArrayList<Character>(); Character[] nums = {‘1‘,‘2‘,‘3‘,‘4‘,‘5‘,‘6‘,‘7‘,‘8‘,‘9‘}; validNum.addAll(Arrays.asList(nums)); table.put(i*row+j, validNum); }else { } } } fillBoard(board); } private void fillBoard(char[][] board) { for (int i = 0; i < row; i++) { System.out.println(); for (int j = 0; j < column; j++) { int index = i*column + j; if (table.containsKey(index)) { // 判断剩余的数字 calRemaingNum(i,j,index,board); } } } System.out.println("++++++++++++++++++++++++++++++++++++++"); if (isSuccess()) { return; } fillBoard(board); } private void calRemaingNum(int i, int j, int calIndex,char[][] board) { //row for(int k=0; k< column; k++){ if (board[i][k] != ‘.‘) { table.get(calIndex).remove((Character)board[i][k]); } } //column for (int k = 0; k < row; k++) { if (board[k][j] != ‘.‘) { table.get(calIndex).remove((Character)board[k][j]); } } //square int m = i / 3; int n = j / 3; for (int k = 0; k < 3; k++) { for (int k2 = 0; k2 < 3; k2++) { if (board[m*3+k][n*3+k2] != ‘.‘) { table.get(calIndex).remove((Character)board[m*3+k][n*3+k2]); } } } System.out.println("i=" + i + " , j = " + j + ",index = " + calIndex + " ++ " + table.get(calIndex)); if (table.get(calIndex).size() == 1) { board[i][j] = table.get(calIndex).get(0); table.remove(calIndex); } } private boolean isSuccess(){ return table.size() == 0; }
别人的
public void solveSudoku(char[][] board) { if (board==null || board.length == 0) { return; } fillboard(board); } private boolean fillboard(char[][] board){ for (int i = 0; i < board.length; i++) { for (int j = 0; j < board[0].length; j++) { if(board[i][j] == ‘.‘){ for(char ch = ‘1‘; ch <= ‘9‘; ch++){ if (isValid(i, j, ch, board)) { System.out.println("ok, i = " + i + ", j = " + j + " , value = " + ch); board[i][j] = ch; if (fillboard(board)) { return true; }else { board[i][j] = ‘.‘; } } } return false; } } } return true; } private boolean isValid(int row, int column, char value, char[][] board){ // row for (int i = 0; i < board.length; i++) { if (board[row][i] == value) { return false; } } // column for (int i = 0; i < board[0].length; i++) { if (board[i][column] == value) { return false; } } // square int m = row / 3; int n = column / 3; for (int k = 0; k < 3; k++) { for (int k2 = 0; k2 < 3; k2++) { if (board[m*3+k][n*3+k2] == value) { return false; } } } return true; }
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原文地址:http://www.cnblogs.com/lingtingvfengsheng/p/4842650.html