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This is the same as SPOJ #453. The best way to understand DP
1A code:
class Solution { public: int minimumTotal(vector<vector<int> > &triangle) { for(size_t i = 1; i < triangle.size(); i ++) { vector<int> &last = triangle[i-1]; vector<int> &curr = triangle[i]; curr[0] = last[0] + curr[0]; for(size_t j = 1; j < curr.size() - 1; j ++) { int picked = last[j-1] < last[j] ? last[j-1] : last[j]; curr[j] += picked; } curr[curr.size() - 1] += last[curr.size() - 2]; } // Get min vector<int> &last = triangle[triangle.size()-1]; return *std::min_element(last.begin(), last.end()); } };
LeetCode "Triangle",布布扣,bubuko.com
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原文地址:http://www.cnblogs.com/tonix/p/3850104.html