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Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0
class Solution { public: int searchInsert(int A[], int n, int target) { if(n==0) return 0; binarySearch(A,0,n-1,target); return result; } void binarySearch(int A[], int start, int end, int target){ //find the first value >= target if(start== end){ if(A[start] < target) result = start+1; else result = start; return; } int mid = start + ((end-start)>>1); //prevent overflow if(A[mid] < target) binarySearch(A,mid+1, end, target); else if(A[mid] > target) binarySearch(A,start, mid, target); else result = mid; } private: int result; };
35. Search Insert Position (Array)
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原文地址：http://www.cnblogs.com/qionglouyuyu/p/4853208.html
