标签:
Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
bool operator < (const Interval &a, const Interval &b){ return a.start < b.start;} class Solution { public: std::vector<Interval> merge(std::vector<Interval> &intervals) { if(intervals.size() == 0) return intervals; std::vector<Interval> res; std::sort(intervals.begin(),intervals.end()); int left = intervals[0].start,right = intervals[0].end; for (int i = 1; i < intervals.size(); i++) { if(intervals[i].start <= right) { right = std::max(right,intervals[i].end); } else { res.push_back(Interval(left,right)); left = intervals[i].start; right = intervals[i].end; } } res.push_back(Interval(left,right)); return res; } };
版权声明:本文博主原创文章,博客,未经同意不得转载。
标签:
原文地址:http://www.cnblogs.com/bhlsheji/p/4853419.html