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Angel was caught by the MOLIGPY! He was put in prison by Moligpy. The prison is described as a N * M (N, M <= 200) matrix. There are WALLs, ROADs, and GUARDs in the prison.
Angel‘s friends want to save Angel. Their task is: approach Angel. We assume that "approach Angel" is to get to the position where Angel stays. When there‘s a guard in the grid, we must kill him (or her?) to move into the grid. We assume that we moving up, down, right, left takes us 1 unit time, and killing a guard takes 1 unit time, too. And we are strong enough to kill all the guards.
You have to calculate the minimal time to approach Angel. (We can move only UP, DOWN, LEFT and RIGHT, to the neighbor grid within bound, of course.)
1 /************************************************************************* 2 > File Name: code/hdu/1242.cpp 3 > Author: 111qqz 4 > Email: rkz2013@126.com 5 > Created Time: 2015年10月02日 星期五 14时38分17秒 6 ************************************************************************/ 7 8 #include<iostream> 9 #include<iomanip> 10 #include<cstdio> 11 #include<algorithm> 12 #include<cmath> 13 #include<cstring> 14 #include<string> 15 #include<map> 16 #include<set> 17 #include<queue> 18 #include<vector> 19 #include<stack> 20 #include<cctype> 21 using namespace std; 22 #define yn hez111qqz 23 #define j1 cute111qqz 24 #define ms(a,x) memset(a,x,sizeof(a)) 25 #define lr dying111qqz 26 const int dx4[4]={1,0,0,-1}; 27 const int dy4[4]={0,-1,1,0}; 28 typedef long long LL; 29 typedef double DB; 30 const int inf = 0x3f3f3f3f; 31 const int N=2E2+5; 32 char maze[N][N]; 33 int m,n; 34 int ans; 35 bool vis[N][N]; 36 struct node 37 { 38 int x,y; 39 int d; 40 41 bool ok () 42 { 43 if (x>=0&&x<n&&y>=0&&y<m&&!vis[x][y]&&maze[x][y]!=‘#‘) return true; 44 return false; 45 } 46 bool hasguard() 47 { 48 if (maze[x][y]==‘x‘) return true; 49 return false; 50 } 51 bool goal() 52 { 53 if (maze[x][y]==‘r‘) return true; 54 return false; 55 } 56 }s; 57 58 bool operator<(const node &a,const node &b) //重载优先级的<关系...返回true时优先级更小,在队列的更后面. 59 { 60 return a.d>b.d; 61 } 62 63 bool bfs() 64 { 65 priority_queue<node>q; 66 q.push(s); 67 68 while (!q.empty()) 69 { 70 node pre = q.top(); 71 q.pop(); 72 // cout<<pre.x<<" "<<pre.y<<" "<<pre.d<<endl; 73 if (pre.goal()) 74 { 75 ans = pre.d; 76 return true; 77 } 78 79 for ( int i = 0 ; i < 4 ; i++) 80 { 81 node next; 82 next.x = pre.x + dx4[i]; 83 next.y = pre.y + dy4[i]; 84 next.d = pre.d + 1; 85 if (!next.ok()) continue; 86 vis[next.x][next.y] = true; 87 if (next.hasguard()) next.d++; 88 q.push(next); 89 90 91 } 92 } 93 return false; 94 } 95 int main() 96 { 97 #ifndef ONLINE_JUDGE 98 freopen("in.txt","r",stdin); 99 #endif 100 while(scanf("%d %d",&n,&m)!=EOF){ 101 ms(vis,false); 102 for ( int i = 0 ; i < n ; i++) scanf("%s",maze[i]); 103 for ( int i = 0 ; i < n ; i++) 104 { 105 for ( int j = 0 ; j < m ; j++) 106 { 107 if (maze[i][j]==‘a‘) 108 { 109 s.x = i ; 110 s.y = j ; 111 s.d = 0 ; 112 vis[i][j] = true; 113 break; 114 } 115 } 116 } 117 118 if (bfs()) 119 { 120 printf("%d\n",ans); 121 } 122 else 123 { 124 puts("Poor ANGEL has to stay in the prison all his life."); 125 } 126 } 127 #ifndef ONLINE_JUDGE 128 fclose(stdin); 129 #endif 130 return 0; 131 }
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原文地址:http://www.cnblogs.com/111qqz/p/4853964.html