码迷,mamicode.com
首页 > 其他好文 > 详细

129. Sum Root to Leaf Numbers(Tree; DFS)

时间:2015-10-04 11:06:49      阅读:121      评论:0      收藏:0      [点我收藏+]

标签:

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   /   2   3

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

class Solution {
public:
    int sumNumbers(TreeNode *root) {
        int sum = 0;
        if(root)
            dfs(root, 0, sum);
        return sum;
        
    }
    void dfs(TreeNode *node, int val, int& sum) {
        val *= 10;
        val += node->val;
        
        if (node->left == NULL && node->right == NULL) {
            sum += val;
            return;
        }
    
        if (node->left) {
            dfs(node->left, val, sum);
        }
        if (node->right) {
            dfs(node->right, val, sum);
        }
    }
};

 

129. Sum Root to Leaf Numbers(Tree; DFS)

标签:

原文地址:http://www.cnblogs.com/qionglouyuyu/p/4854207.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!