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LeetCode OJ:Add Binary(二进制相加)

时间:2015-10-11 22:51:57      阅读:233      评论:0      收藏:0      [点我收藏+]

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Given two binary strings, return their sum (also a binary string).

For example,
a = "11"
b = "1"
Return "100".

简单的二进制相加而已,只不过传入的参数是字符串而已。为了方便,先将string  reverse了一下,代码如下:

 1 class Solution {
 2 public:
 3     string addBinary(string a, string b) {
 4         reverse(a.begin(), a.end());
 5         reverse(b.begin(), b.end());
 6         int len1 = a.length();
 7         int len2 = b.length();
 8         string result;
 9         int flag ,val;
10         flag = val = 0;
11         int i;
12         for(i = 0; i < len1 && i < len2; ++i){
13             val = (a[i] - 0) + (b[i] - 0) + flag;
14             result.append(1, val % 2 + 0);
15             flag = val/2;
16         }
17         while (i < len1) {
18             val = a[i] - 0+ flag;
19             result.append(1, val % 2 + 0);
20             flag = val/2;
21             ++i;
22         }
23         while (i < len2 ){
24             val = b[i] - 0+ flag;
25             result.append(1, val % 2 + 0);
26             flag = val/2;
27             ++i;
28         }
29         cout << "flag " << flag << endl;
30         if(flag != 0)
31             result.append(1, 1);
32         reverse(result.begin(), result.end());
33         return result;
34     }
35 };

 

LeetCode OJ:Add Binary(二进制相加)

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原文地址:http://www.cnblogs.com/-wang-cheng/p/4870243.html

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