码迷,mamicode.com
首页 > 其他好文 > 详细

Leetcode Flip Game II

时间:2015-10-17 01:51:01      阅读:294      评论:0      收藏:0      [点我收藏+]

标签:

You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip twoconsecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to determine if the starting player can guarantee a win.

For example, given s = "++++", return true. The starting player can guarantee a win by flipping the middle "++" to become "+--+".

Follow up:
Derive your algorithm‘s runtime complexity.


解题思路:

backtracking


Java code

public class Solution {
    public boolean canWin(String s) {
        for(int i = 0; i < s.length()-1; i++){
            if(s.charAt(i) == ‘+‘ && s.charAt(i+1) == ‘+‘ && !canWin(s.substring(0,i)+"--" + s.substring(i+2))){
                return true;
            }
        }
        return false;
    }
}

Reference:

1. https://leetcode.com/discuss/64330/4-line-java-solution

2. https://leetcode.com/discuss/64357/memoization-3150ms-130ms-44ms-python

 

Leetcode Flip Game II

标签:

原文地址:http://www.cnblogs.com/anne-vista/p/4886786.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!