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/** * 功能: * 1、去除字符串两边的空白字符 * 2、将字符串中间的连续空白字符压缩为一个空格 * * 时间:2015/10/17 15:10:49 * 作者:小代码 * */ #include<stdio.h> #include<string.h> #include<ctype.h> #include<stdlib.h> /** * @brief 将字符串两人边的空白字符删除,并返回一个新的字符串 * * @param str 要处理的字符串 * * @return 返回删除两边空白字符的新字符串 */ char * str_trim( char * str ){ int str_len = strlen( str ); int begin = 0; int end = str_len - 1; int i = 0; while( isspace( str[ begin++ ] ) ) ; begin--; while( isspace( str[ end-- ] ) ) ; end++; char *t = ( char* )malloc( sizeof( char )*( end - begin + 2 ) ); i = 0; while( begin <= end && ( t[ i++ ] = str[ begin++ ] )) ; t[ i ] = ‘\0‘; return t; } /** * @brief 将字符串中间的空白字符压缩为一个空格,并返回新的字符串 * * @pre 字符串两人边不能有空白字符 * @param 要处理的字符串 * * @return 返回连续空白转换为一个空格的字符串 * */ char * str_constrict_space( char * str ){ int str_len = strlen( str ); char * t = ( char* )malloc( sizeof( str_len ) * str_len ); int i = -1; int j = 0; while( i++ < str_len ){ if( !isspace( str[ i ] ) ){ t[ j++ ] = str[ i ]; }else{ if( !isspace( str[ i+1 ] ) ){ t[ j++ ] = ‘ ‘; } } } t[ j ] = ‘\0‘; return t; } int main( void ){ char str[ 30 ]; fgets( str,30,stdin ); char * t = str_trim( str ); printf( "**%s**\n",t ); t = str_constrict_space( t ); printf( "%s\n", t); }
运行效果:
[laolang@laolang string]$ make exec ./hello 123 456 **123 456** 123 456 [laolang@laolang string]$
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原文地址:http://my.oschina.net/iamhere/blog/518280