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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.
1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * int val; 5 * ListNode *next; 6 * ListNode(int x) : val(x), next(NULL) {} 7 * }; 8 */ 9 10 class Solution { 11 public: 12 void deleteNode(ListNode* node) { 13 if(node == NULL) return; 14 node->val = node->next->val; 15 node->next = node->next->next; 16 } 17 };
LeetCode OJ：Delete Node in a Linked List（链表节点删除）
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原文地址：http://www.cnblogs.com/-wang-cheng/p/4889053.html
