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Treap的基础题目,Treap是个挺不错的数据结构。
1 /* */ 2 #include <iostream> 3 #include <string> 4 #include <map> 5 #include <queue> 6 #include <set> 7 #include <stack> 8 #include <vector> 9 #include <deque> 10 #include <algorithm> 11 #include <cstdio> 12 #include <cmath> 13 #include <ctime> 14 #include <cstring> 15 #include <climits> 16 #include <cctype> 17 #include <cassert> 18 #include <functional> 19 #include <iterator> 20 #include <iomanip> 21 using namespace std; 22 //#pragma comment(linker,"/STACK:102400000,1024000") 23 24 #define sti set<int> 25 #define stpii set<pair<int, int> > 26 #define mpii map<int,int> 27 #define vi vector<int> 28 #define pii pair<int,int> 29 #define vpii vector<pair<int,int> > 30 #define rep(i, a, n) for (int i=a;i<n;++i) 31 #define per(i, a, n) for (int i=n-1;i>=a;--i) 32 #define clr clear 33 #define pb push_back 34 #define mp make_pair 35 #define fir first 36 #define sec second 37 #define all(x) (x).begin(),(x).end() 38 #define SZ(x) ((int)(x).size()) 39 #define lson l, mid, rt<<1 40 #define rson mid+1, r, rt<<1|1 41 42 typedef struct { 43 char c; 44 int x, y; 45 } Cmd; 46 47 typedef struct Node { 48 Node* ch[2]; 49 int r, v, s; 50 51 Node() {} 52 53 Node(int v_) { 54 ch[0] = ch[1] = NULL; 55 r = rand(); 56 v = v_; 57 s = 1; 58 } 59 60 friend bool operator<(const Node& a, const Node& b) { 61 return a.r < b.r; 62 } 63 64 int cmp(int x) const { 65 if (x == v) return -1; 66 return x<v ? 0:1; 67 } 68 69 void maintain() { 70 s = 1; 71 if (ch[0] != NULL) s += ch[0]->s; 72 if (ch[1] != NULL) s += ch[1]->s; 73 } 74 75 } Node; 76 77 void rotate(Node*& o, int d) { 78 Node* k = o->ch[d^1]; 79 o->ch[d^1] = k->ch[d]; 80 k->ch[d] = o; 81 o->maintain(); 82 k->maintain(); 83 o = k; 84 } 85 86 void insert(Node*& o, int x) { 87 if (o == NULL) { 88 o = new Node(x); 89 } else { 90 int d = x<o->v ? 0:1; 91 insert(o->ch[d], x); 92 if (o->ch[d]->r > o->r) 93 rotate(o, d^1); 94 } 95 o->maintain(); 96 } 97 98 void remove(Node*& o, int x) { 99 int d = o->cmp(x); 100 101 if (d == -1) { 102 Node* u = o; 103 if (o->ch[0]!=NULL && o->ch[1]!=NULL) { 104 int d2 = o->ch[0]->r > o->ch[1]->r ? 1:0; 105 rotate(o, d2); 106 remove(o->ch[d2], x); 107 } else { 108 if (o->ch[0] == NULL) 109 o = o->ch[1]; 110 else 111 o = o->ch[0]; 112 delete u; 113 } 114 } else { 115 remove(o->ch[d], x); 116 } 117 if (o != NULL) 118 o->maintain(); 119 } 120 121 const int maxc = 5e5+5; 122 const int maxn = 2e4+5; 123 const int maxm = 6e4+5; 124 Cmd cmd[maxc]; 125 Node* rt[maxn]; 126 int W[maxn], pre[maxn]; 127 int U[maxm], V[maxm]; 128 bool mark[maxm]; 129 130 int find(int x) { 131 if (x == pre[x]) 132 return x; 133 return pre[x] = find(pre[x]); 134 } 135 136 void removetree(Node*& x) { 137 if (x->ch[0] != NULL) removetree(x->ch[0]); 138 if (x->ch[1] != NULL) removetree(x->ch[1]); 139 delete x; 140 x = NULL; 141 } 142 143 void mergeto(Node*& src, Node*& des) { 144 if (src->ch[0] != NULL) mergeto(src->ch[0], des); 145 if (src->ch[1] != NULL) mergeto(src->ch[1], des); 146 insert(des, src->v); 147 delete src; 148 src = NULL; 149 } 150 151 void addEdge(int k) { 152 int u = U[k], v = V[k]; 153 int fu = find(u), fv = find(v); 154 155 if (fu != fv) { 156 if (rt[fu]->s < rt[fv]->s) { 157 pre[fu] = fv; 158 mergeto(rt[fu], rt[fv]); 159 } else { 160 pre[fv] = fu; 161 mergeto(rt[fv], rt[fu]); 162 } 163 } 164 } 165 166 int kth(Node* o, int k) { 167 if (o==NULL || k<=0 || k>o->s) 168 return 0; 169 170 int s = o->ch[1]==NULL ? 0:o->ch[1]->s; 171 if (k == s+1) 172 return o->v; 173 else if (k <= s) 174 return kth(o->ch[1], k); 175 else 176 return kth(o->ch[0], k-s-1); 177 } 178 179 int main() { 180 ios::sync_with_stdio(false); 181 #ifndef ONLINE_JUDGE 182 freopen("data.in", "r", stdin); 183 freopen("data.out", "w", stdout); 184 #endif 185 186 int tt = 0; 187 int n, m, nc; 188 int x, y; 189 char s[3]; 190 __int64 tot, ans; 191 192 while (scanf("%d %d",&n,&m)!=EOF && (n||m)) { 193 rep(i, 1, n+1) 194 scanf("%d", &W[i]); 195 rep(i, 1, m+1) 196 scanf("%d %d", &U[i], &V[i]); 197 198 memset(mark, false, sizeof(mark)); 199 nc = 0; 200 while (scanf("%s", s)!=EOF && s[0]!=‘E‘) { 201 cmd[nc].c = s[0]; 202 if (s[0] == ‘D‘) { 203 scanf("%d", &x); 204 cmd[nc].x = x; 205 mark[x] = true; 206 } else if (s[0] == ‘Q‘) { 207 scanf("%d %d", &x, &y); 208 cmd[nc].x = x; 209 cmd[nc].y = y; 210 } else if (s[0] == ‘C‘) { 211 scanf("%d %d", &x, &y); 212 cmd[nc].x = x; 213 cmd[nc].y = W[x]; 214 W[x] = y; 215 } 216 ++nc; 217 } 218 219 220 rep(i, 1, n+1) { 221 pre[i] = i; 222 if (rt[i] != NULL) 223 removetree(rt[i]); 224 rt[i] = new Node(W[i]); 225 } 226 227 rep(i, 1, m+1) { 228 if (!mark[i]) 229 addEdge(i); 230 } 231 232 ans = tot = 0; 233 per(i, 0, nc) { 234 if (cmd[i].c == ‘D‘) { 235 addEdge(cmd[i].x); 236 } else if (cmd[i].c == ‘Q‘) { 237 int fx = find(cmd[i].x); 238 ++tot; 239 ans += kth(rt[fx], cmd[i].y); 240 } else if (cmd[i].c == ‘C‘) { 241 int fx = find(cmd[i].x); 242 remove(rt[fx], W[cmd[i].x]); 243 insert(rt[fx], cmd[i].y); 244 W[cmd[i].x] = cmd[i].y; 245 } 246 } 247 printf("Case %d: %.06lf\n", ++tt, 1.0*ans/tot); 248 } 249 250 #ifndef ONLINE_JUDGE 251 printf("time = %d.\n", (int)clock()); 252 #endif 253 254 return 0; 255 }
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原文地址:http://www.cnblogs.com/bombe1013/p/4894292.html