码迷,mamicode.com
首页 > 其他好文 > 详细

LintCode "Triangle Count"

时间:2015-10-21 08:06:15      阅读:286      评论:0      收藏:0      [点我收藏+]

标签:

Should be "Medium" or even "Easy".. Just with a little Greedy.

class Solution {
public:
    /**
     * @param S: A list of integers
     * @return: An integer
     */
    int triangleCount(vector<int> &S) {
        int n = S.size();
        if(n < 3) return 0;
        
        sort(S.begin(), S.end());
        int ret = 0;
        
        for(int e = n - 1; e > 1; e --)
        {
            int s = 0, m = e - 1;
            while(s < m)
            {
                if( (S[s] + S[m]) <= S[e])
                {
                    s ++;
                }
                else
                {
                    ret += m - s;
                    m --;
                }
            }
        }
        
        return ret;
    }
};

LintCode "Triangle Count"

标签:

原文地址:http://www.cnblogs.com/tonix/p/4896680.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!