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[POJ1969]Count on Canton

时间:2015-10-25 16:21:35      阅读:139      评论:0      收藏:0      [点我收藏+]

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NOIP1999普及组

Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 9333   Accepted: 5469

Description

One of the famous proofs of modern mathematics is Georg Cantor‘s demonstration that the set of rational numbers is enumerable. The proof works by using an explicit enumeration of rational numbers as shown in the diagram below. 
1/1 1/2 1/3 1/4 1/5 ...

2/1 2/2 2/3 2/4
3/1 3/2 3/3
4/1 4/2
5/1

In the above diagram, the first term is 1/1, the second term is 1/2, the third term is 2/1, the fourth term is 3/1, the fifth term is 2/2, and so on.

Input

The input list contains a single number per line and will be terminated by endof-file.

Output

You are to write a program that will read a list of numbers in the range from 1 to 10^7 and will print for each number the corresponding term in Cantor‘s enumeration as given below.

Sample Input

3
14
7

Sample Output

TERM 3 IS 2/1
TERM 14 IS 2/4
TERM 7 IS 1/4

Source

Solutions

  模拟打一个Cantor表。

技术分享
var n,i,m:longint;
procedure main;
begin
    readln(n);
    m:=n;
    i:=1;
    while n>i do
        begin
            dec(n,i);
            inc(i)
        end;
    if i mod 2=1 then writeln(TERM ,m, IS ,i+1-n,/,n)
    else writeln(TERM ,m, IS ,n,/,i+1-n);
end;
begin
    while not seekeof do
        main;
end.
View Code

 

[POJ1969]Count on Canton

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原文地址:http://www.cnblogs.com/yangqingli/p/4908797.html

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