标签：
Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn‘t matter what you leave beyond the new length.
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解题：
简单
class Solution {
public:
int removeElement(vector<int>& nums, int val) {
int now = -1;
for(int i = 0; i<nums.size();i++){
if(nums[i]!=val){
nums[++now] = nums[i];
}
}
return now+1;
}
};
leetcode_27_ Remove Element (easy)
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原文地址：http://www.cnblogs.com/ganeveryday/p/4929635.html
