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package cn.edu.xidian.sselab;
/**
* title:Same Tree
* content:
* Given two binary trees, write a function to check if they are equal or not.
* Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
*/
public class SameTree {
/**
* @author wzy
* @param args
* @see 判断两棵树是否相同,不仅要看结构,同时也要看每个节点对应的值
* 首先想到的是对树分别进行遍历,遍历想到了递归
* 遍历采用的是后序遍历的方式,同时遍历都叶子节点之后要考虑四种情况
* (1)如果对应的节点都是null,则返回true
* (2)如果其中一个节点为null,另外一个节点不为null,则返回false
* (3)如果两个节点都不为null,但是数值不相等 ,返回false
* (4)如果两个节点都不为null,而且数值相等,则进行递归操作
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
}
public class TreeNode{
int val;
TreeNode left;
TreeNode right;
TreeNode(int x){
this.val = x;
}
}
public boolean isSameTree(TreeNode p, TreeNode q){
boolean flag1 = false;
boolean flag2 = false;
if(p == null && q == null ){
return true;
}else if((p == null || q == null)){
return false;
}else if(p.val != q.val){
return false;
}else{
flag1 = isSameTree(p.left,q.left);
flag2 = isSameTree(p.right,q.right);
}
return (flag1 && flag2);
}
}
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原文地址:http://www.cnblogs.com/wzyxidian/p/4937618.html