标签:
Time Limit: 2000MS | Memory Limit: 10000K | |
Total Submissions: 1450 | Accepted: 846 |
Description
Input
Output
Sample Input
10 25 100
Sample Output
1 4 4 9 16 27
Source
1 #include <cstdio> 2 #include <cstring> 3 #include <iostream> 4 #include <stack> 5 #include <queue> 6 #include <map> 7 #include <algorithm> 8 #include <vector> 9 #include <cmath> 10 11 using namespace std; 12 13 const int maxn = 1000001; 14 15 typedef long long LL; 16 17 bool flag[maxn]; 18 19 int gcd(int a,int b) 20 { 21 if(b == 0) return a; 22 else return gcd(b,a%b); 23 } 24 void solve(int t) 25 { 26 int temp,m,i,j,k,n,ans1,ans2,x,y,z; 27 memset(flag,0,sizeof(flag)); 28 temp = sqrt(t+0.0); 29 ans1 = ans2 = 0; 30 for( i=1;i<=temp;i++){ 31 for(j = i+1;j<=temp;j++){ 32 if(i*i + j*j > t) break; 33 if((i%2) != (j%2)){ 34 if(gcd(i,j) == 1){ 35 x = j*j - i*i; 36 y = 2*i*j; 37 z = j*j + i*i; 38 ans1++; 39 for( k=1;;k++){ 40 if( k*z > t) break; 41 flag[k*x] = 1; 42 flag[k*y] = 1; 43 flag[k*z] = 1; 44 } 45 } 46 } 47 } 48 } 49 for(int i=1;i<=t;i++){ 50 if(!flag[i]) ans2++; 51 } 52 printf("%d %d\n",ans1,ans2); 53 } 54 int main() 55 { 56 int n; 57 while(scanf("%d",&n)!=EOF){ 58 solve(n); 59 } 60 return 0; 61 }
标签:
原文地址:http://www.cnblogs.com/lmlyzxiao/p/4937697.html