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题目:
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.
According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has both v and w as descendants (where we allow a node to be a descendant of itself).”
_______6______ / ___2__ ___8__ / \ / 0 _4 7 9 / 3 5
For example, the lowest common ancestor (LCA) of nodes 2
and 8
is 6
. Another example is LCA of nodes 2
and 4
is 2
, since a node can be a descendant of itself according to the LCA definition.
解析:
在二叉查找树种,寻找两个节点的最低公共祖先。
1、如果a、b都比根节点小,则在左子树中递归查找公共节点。
2、如果a、b都比根节点大,则在右子树中查找公共祖先节点。
3、如果a、b一个比根节点大,一个比根节点小,或者有一个等于根节点,则根节点即为最低公共祖先。
1 /** 2 * Definition for a binary tree node. 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */ 10 class Solution { 11 public: 12 TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) { 13 if(root->val > max(p->val,q->val) ) 14 return lowestCommonAncestor(root->left,p,q); 15 if(root->val < min(p->val,q->val) ) 16 return lowestCommonAncestor(root->right,p,q); 17 return root; 18 } 19 };
Lowest Common Ancestor of a Binary Search Tree
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原文地址:http://www.cnblogs.com/raichen/p/4938375.html