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Description
Input
Output
Sample Input
Sample Output
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<queue>
#include<vector>
using namespace std;
const int maxn = 1010;
const int INF = 0x3f3f3f3f;
struct Edge{
int from,to,dist,next;
Edge(){}
Edge(int _to,int _next,int _dist):to(_to),next(_next),dist(_dist){}
}edges[maxn*maxn*2];
int tot , head[maxn];
int dfn[maxn], bridge[maxn], dfs_clock, low[maxn], brinum;
int Mins;
void init(){
tot = 0;
dfs_clock = 0;
brinum = 0;
Mins = INF;
memset(head,-1,sizeof(head));
memset(dfn,0,sizeof(dfn));
memset(bridge,0,sizeof(bridge));
}
void AddEdge(int _u,int _v,int _w){
edges[tot] = Edge(_v,head[_u],_w);
head[_u] = tot++;
}
int dfs(int u,int fa){
int lowu = dfn[u] = ++dfs_clock;
for(int i = head[u]; i != -1; i = edges[i].next){
int v = edges[i].to;
if(!dfn[v]){
int lowv = dfs(v,i);
lowu = min(lowu,lowv);
if(lowv > dfn[u]){
bridge[v] = 1;
brinum++;
Mins = min(Mins , edges[i].dist);
}
}else if(dfn[v] < dfn[u] && (fa^1) != i){
lowu = min(dfn[v],lowu);
}
}
low[u] = lowu;
return lowu;
}
int main(){
int n,m;
while(scanf("%d%d",&n,&m)!=EOF&&(n+m)){
int a,b,c;
init();
for(int i = 0; i <m ;i++){
scanf("%d%d%d",&a,&b,&c);
AddEdge(a,b,c);
AddEdge(b,a,c);
}
int times = 0;
for(int i = 1; i <= n; i++){
if(!dfn[i]){
times++;
dfs(i,-1);
}
}
if(times > 1){
puts("0");
continue;
}
if(brinum == 0){
puts("-1");
continue;
}
printf("%d\n",Mins == 0? 1:Mins);
}
return 0;
}
HDU 4738——Caocao's Bridges——————【求割边/桥的最小权值】
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原文地址:http://www.cnblogs.com/chengsheng/p/4943421.html