LeetCode237-Delete Node in a Linked List

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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

题意很简单很简单，删除单链表中指定的结点，仔细一看，不对啊。。无法得到要删除结点的前驱结点，也就是说不能用传统的方法。如果单链表1->2->3->4->5,我们要删除结点3，可以让3赋值为4，3指向5。那么就变成了1->2->4->5，^_^结果就得到了

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     struct ListNode *next;
 * };
 */
void deleteNode(struct ListNode* node) {
    if(node==NULL)
    {
        return ;
    }
    else
    {
        node->val=node->next->val;
        node->next=node->next->next;
    }
}

LeetCode237-Delete Node in a Linked List

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原文地址：http://www.cnblogs.com/liuyifei/p/Delete_Node_in_a_Linked_List.html