合并两个排好序的链表,并返回这个新链表。
新链表应该由这两个链表的头部拼接而成。
Merge two sorted linked lists and return it as a new list.
The new list should be made by splicing together the nodes of the first two lists.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
if(l2 == NULL) {
return l1;
}
if(l1 == NULL) {
return l2;
}
if(l1->val > l2->val) {
ListNode* temp = l2;
temp->next = mergeTwoLists(l1, l2->next);
return temp;
} else {
ListNode* temp = l1;
temp->next = mergeTwoLists(l1->next, l2);
return temp;
}
}
};
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LeetCode 21 Merge Two Sorted Lists
原文地址:http://blog.csdn.net/nomasp/article/details/49764883