有如下值集合 [11,22,33,44,55,66,77,88,99,90...]，将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。
即： {‘k1‘: 大于66 , ‘k2‘: 小于66}

v1 = [11,22,33,44,55,66,77,88,99,90]
dicNum = {"k1":[],"k2":[]}

for i in v1:
    if int(i) > 66:
        dicNum["k1"].append(i)
    else:
        dicNum["k2"].append(i)
print dicNum["k1"]
print dicNum["k2"]
print dicNum

v2 = [11,22,33,44,55,66,77,88,99,90]
dicNum = {}
for i in v2:
    if int(i) > 66:
        if "k1" in dicNum:
            dicNum["k1"].append(i)
        else:
            dicNum["k1"] = [i]
    else:
        if "k2" in dicNum:
            dicNum["k2"].append(i)
        else:
            dicNum["k2"] = [i]
print dicNum["k1"]
print dicNum["k2"]

# 默认字典
myDict = collections.defaultdict(list)
myDict["k1"].append(1)
print myDict["k1"]

# 有序字典 orderdict

有序字典是在字典里面维护了一个列表

#计数器counter

list1 = [11,22,33,44,5544,3322,111]
tuple1 = (11,22,33,44,222,5555,2222)
str1 = "2343252632642362hfidsafhsifoesagoewagewaglsanldsa;lsf;sahflaf;saf;la"
c2 = collections.Counter(str1)
print c2

import Queue
q = Queue.Queue()
q.put(2)
q.put(3)
q.put(23)
print q.get()

练习：<br>有如下列表：
    [13, 22, 6, 99, 11]
 
请按照一下规则计算：
13 和 22 比较，将大的值放在右侧，即：[13, 22, 6, 99, 11]
22 和 6 比较，将大的值放在右侧，即：[13, 6, 22, 99, 11]
22 和 99 比较，将大的值放在右侧，即：[13, 6, 22, 99, 11]
99 和 42 比较，将大的值放在右侧，即：[13, 6, 22, 11, 99,]
 
13 和 6 比较，将大的值放在右侧，即：[6, 13, 22, 11, 99,]
...

li = [13, 22, 6, 99, 11]

for m in range(len(li)-1):

    for n in range(m+1, len(li)):
        if li[m]> li[n]:
            temp = li[n]
            li[n] = li[m]
            li[m] = temp

print li

def func(*args):
    print args


li = [11,22,33,444,332,112]
func(*li)

def func(**args):
    print args

dic = {"echo":123,"rep":234}
func(**dic)

def email(arg):
    print arg


if __name__ == "__main__":
    cpu = 100
    ram = 50
    disk = 500
    for i in range(1):
        if cpu > 90:
            alert = "cpu 出现问题"
            email(alert)
        if disk > 90:
            alert = "disk 出现问题"
            email(alert)
        if ram > 80:
            alert = "内存 出现问题"
            email(alert)

obj = open("index.txt","r")

obj.seek(10)
#定位指针

print obj.tell()
#输出指针位置

print obj.read()
#输出内容

print obj.tell()

#输出指针位置