学生——成绩表2.2

select distinct Student.* 
from Student , SCore , Course , Teacher
where Student.s_id= SCore.s_id and SCore.C_id = Course.C_id and Course.T_id = Teacher.T_id and Teacher.Tname = ‘张三‘
order by Student.S_id

select student.* 
from student 
where student.S_id not in
(select distinct score.S_id from score , course , teacher where score.C_id = course.C_id and course.T_id = teacher.T_id and teacher.tname = N‘张三‘)
order by student.S_id

select student.* from student where S_id in
(select S_id from score group by S_id having count(1) = (select count(1) from course))

select t.* from student t where t.S_id not in(
  select distinct m.S_id from
  ( select S_id , C_id from student , course) m where not exists (select 1 from score n where n.S_id = m.S_id and n.C_id = m.C_id)
)

select t.* from student t where not exists(select 1 from(
select distinct m.S_id from(
select S_id , C_id from student , course) m where not exists (select 1 from score n where n.S_id = m.S_id and n.C_id = m.C_id)
) k where k.S_id = t.S_id)

select Student.*
from Student , SCore
where Student.S_id = SCore.S_id
group by Student.S_id , Student.Sname , Student.Sage , Student.Ssex having count(C_id) < (select count(C_id) from Course)

select Student.*
from Student left join SCore
on Student.S_id = SCore.S_id
group by Student.S_id , Student.Sname , Student.Sage , Student.Ssex having count(C_id) < (select count(C_id) from Course)

select Student.S_id, Student.Sname
from Student , SCore
where Student.S_id = SCore.S_id
group by Student.S_id , Student.Sname
having count(SCore.S_id) = 2
order by Student.S_id

select student.S_id, student.Sname
from student , SCore
where student.S_id = SCore.S_id
group by student.S_id , student.Sname
having count(1) >= 2
order by student.S_id

select c_id , count(S_id) 学生数 from score group by c_id

select Course.C_id , Course.Cname , count(*) 学生人数
from Course , SCore
where Course.C_id = SCore.C_id
group by  Course.C_id , Course.Cname
order by Course.C_id , Course.Cname

select Course.C_id, Course.Cname , count(*) 学生人数
from Course , SCore
where Course.C_id = SCore.C_id
group by  Course.C_id , Course.Cname
having count(*) >= 5
order by 学生人数 desc , Course.C_id

select Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id= ‘01‘ and exists (
Select 1 from SCore SC_2 where SC_2.S_id = SCore.S_id and SC_2.C_id= ‘02‘) 
order by Student.S_id

select Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id = ‘02‘ and exists (Select 1 from SCore SC_2 where SC_2.S_id = SCore.S_id and SC_2.C_id = ‘01‘) 
order by Student.S_id

select m.* from Student m where S_id in(
  select S_id from(
     select distinct S_id from SCore where C_id = ‘01‘
     union all
     select distinct S_id from SCore where C_id = ‘02‘
  ) t group by S_id having count(1) = 2
) order by m.S_id

select Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id = ‘01‘ and not exists (
Select 1 from SCore SC_2 where SC_2.S_id = SCore.S_id and SC_2.C_id = ‘02‘) 
order by Student.S_id

select Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id = ‘01‘ and Student.S_id not in (
Select SC_2.S_id from SCore SC_2 where SC_2.S_id = SCore.S_id and SC_2.C_id = ‘02‘) 
order by Student.S_id

select Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id= ‘01‘ and exists (
Select 1 from SCore SC_2 where SC_2.S_id = SCore.S_id and SC_2.C_id= ‘02‘) and not exists(
Select 1 from SCore SC_3 where SC_3.S_id = SCore.S_id and SC_3.C_id= ‘03‘)
order by Student.S_id

select distinct Student.* from Student , SCore 
where Student.S_id = SCore.S_id and SCore.C_id in (select C_id from SCore where S_id = ‘01‘) and Student.S_id <> ‘01‘

select Student.* from Student where S_id in
(select distinct SCore.S_id from SCore where S_id <> ‘01‘ and SCore.C_id in (select distinct C_id from SCore where S_id = ‘01‘)
group by SCore.S_id having count(1) = (select count(1) from SCore where S_id=‘01‘))