HDU-5504(逻辑if-else大水题)

#include <iostream>
#include <algorithm>
#include <cstdio>
using namespace std;

int main()
{
    int T;
    __int64 t;
    scanf("%d",&T);
    while(T--)
    {
        __int64 ans = 1;
        __int64 a[65];
        int n;
        int q = 0,f = 0; 
        scanf("%d",&n);
        for(int i = 1;i <= n;i++) {
            scanf("%I64d",&t);
            if(t > 0) ans *= t;
            else if(t == 0) f++;
            else a[++q] = t;
        }
        //把0会造成影响的两种特殊情况拿出来处理一下 
        if(q+f == n) {
            if(!q) {
                printf("0\n");
                continue;
            }
            if(q == 1) {
                if(!f) {printf("%I64d\n",a[1]);continue;}
                if(f) {printf("0\n");continue;}
            }
        }
        //如果有正数存在 
        if(q%2 == 0) {
            for(int i = 1;i <= q;i++)
                ans *= a[i];
            printf("%I64d\n",ans);
            continue;
        }
        else {
            sort(a+1,a+1+q);
            for(int i = 1;i <= q-1;i++)
                ans *= a[i];
            printf("%I64d\n",ans);
            continue;
        }
    }
)   return 0;
}