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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6875 Accepted Submission(s): 3191
/* ID: LinKArftc PROG: 3336.cpp LANG: C++ */ #include <map> #include <set> #include <cmath> #include <stack> #include <queue> #include <vector> #include <cstdio> #include <string> #include <utility> #include <cstdlib> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define eps 1e-8 #define randin srand((unsigned int)time(NULL)) #define input freopen("input.txt","r",stdin) #define debug(s) cout << "s = " << s << endl; #define outstars cout << "*************" << endl; const double PI = acos(-1.0); const double e = exp(1.0); const int inf = 0x3f3f3f3f; const int INF = 0x7fffffff; typedef long long ll; const int maxn = 200010; const int MOD = 10007; int dp[maxn]; char str[maxn]; int Next[maxn]; void getNext(char *p) { int i = 0, j = -1; int len = strlen(p); Next[0] = -1; while (i < len) { if (j == -1 || p[i] == p[j]) { i ++; j ++; Next[i] = j; } else j = Next[j]; } } int main() { int T, n; scanf("%d", &T); while (T --) { scanf("%d", &n); scanf("%s", str); getNext(str); dp[0] = 0; int ans = 0; for (int i = 1; i <= n; i ++) { dp[i] = (dp[Next[i]] + 1) % MOD; ans = (dp[i] + ans) % MOD; } printf("%d\n",ans); } return 0; }
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原文地址:http://www.cnblogs.com/LinKArftc/p/4959434.html