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http://acm.hdu.edu.cn/showproblem.php?pid=4325
Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 2577 Accepted Submission(s): 1263
#include<iostream> #include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> #include<queue> using namespace std; #define N 110000 #define MOD 100000007 #define Lson r<<1 #define Rson r<<1|1 struct node { int L, R, e; int Mid() { return (L+R)/2; } }a[N<<2]; void BuildTree(int r, int L, int R) { a[r].L=L, a[r].R=R, a[r].e=0; if(L==R) return ; BuildTree(Lson, L, a[r].Mid()); BuildTree(Rson, a[r].Mid()+1, R); } void Update(int r, int L, int R) { if(a[r].L==L && a[r].R==R) { a[r].e++; return ; } if(R<=a[r].Mid()) return Update(Lson, L, R); else if(L>a[r].Mid()) return Update(Rson, L, R); else { Update(Lson, L, a[r].Mid()); Update(Rson, a[r].Mid()+1, R); } } void UP(int r, int L, int R) { if(L==R) return ; if(a[r].L==L && a[r].R==R ) { a[Lson].e += a[r].e; a[Rson].e += a[r].e; } if(R<=a[r].Mid()) UP(Lson, L, R); else if(L>a[r].Mid()) UP(Rson, L, R); else { UP(Lson, L, a[r].Mid()); UP(Rson, a[r].Mid()+1, R); } } int Query(int r, int x) { if(a[r].L==a[r].R && a[r].L==x) return a[r].e; if(x<=a[r].Mid()) return Query(Lson, x); else return Query(Rson, x); } int main() { int T, iCase=1; scanf("%d", &T); while(T--) { int n, m, i, L, R, x; scanf("%d%d", &n, &m); BuildTree(1, 1, 100005); for(i=0; i<n; i++) { scanf("%d%d", &L, &R); Update(1, L, R); } UP(1, 1, 100005); printf("Case #%d:\n", iCase++); for(i=0; i<m; i++) { scanf("%d", &x); printf("%d\n", Query(1, x)); } } return 0; }
(线段树 区间运算求点)Flowers -- hdu -- 4325
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原文地址:http://www.cnblogs.com/YY56/p/4965021.html