标签：
POJ1979
Description
There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can‘t move on red tiles, he can move only on black tiles.
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.
Output
#include <stdio.h>
#define MAX_H 20
int map[MAX_H][MAX_H];
int visited[MAX_H][MAX_H];
int height;
int width;
int resultCount = 0;
int arr[4][2] = {{0,1},{1,0},{0,-1},{-1,0}}; //right down left up
int dfs(int x, int y);
int main()
{
//freopen("input.txt","r",stdin);
int i = 0;
int j = 0;
char tempChar;
scanf("%d %d",&width,&height);
int startWidth = 0;
int startHeight = 0;
while(!(width==0 && height==0))
{
resultCount = 1;
for(i=0;i<height;i++)
{
for(j=0;j<width;j++)
{
visited[i][j] = 0;
scanf(" %c",&tempChar);
if(tempChar==‘.‘)
{
map[i][j] = 0;
}
else if(tempChar==‘#‘)
{
map[i][j] = 1;
}
else if(tempChar==‘@‘)
{
map[i][j] = 2;
startWidth = j;
startHeight = i;
}
}
}
dfs(startHeight,startWidth);
printf("%d\n",resultCount);
scanf(" %d %d",&width,&height);
}
return 0;
}
int dfs(int x, int y)
{
int i = 0;
int tempx = 0;
int tempy = 0;
for(i=0;i<4;i++)
{
tempx = x + arr[i][0];
tempy = y + arr[i][1];
if(tempx>=0 && tempx<height && tempy>=0 && tempy<width)
{
if(map[tempx][tempy]==0 && visited[tempx][tempy]==0)
{
visited[tempx][tempy] = 1;
resultCount++;
dfs(tempx,tempy);
}
}
}
return 0;
}
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原文地址：http://www.cnblogs.com/xuxu-ning/p/4970684.html
