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A Easy C Program Problem

标签（空格分隔）： 学习 C

找幸运数

题目描述

数字8最多的那个数为幸运数。 输入n和n个整数，找这n个数中的幸运数。在主函数中调用ndigit函数，判断某个整数x含数字8的个数。如果有多个幸运数输出第一个幸运数，如果所有的数中都没有含数字8，则输出NO.

函数int ndigit（int n,int k)功能：统计整数n中含数字k的个数。

输入描述

输入n个n个整数

输出描述

幸运数

输入样例

5 568 567 328 48768 8688

输出样例

8688

ANSWER(with a little presentation error)

#include <stdio.h>
#include <stdlib.h>

//I think I should improve my POOR English, so all the comments are written in English

int ndigit (int n, int k);

int main()
{
    /**
     * @param n INPUT 1
     * @param num the temp of the number in INPUT
     * @param luckyNum the lucky number
     * @param luckyDigCount the count of lucky digit in the lucky number
     */
    int n, i, num, luckyNum = 0, luckyDigCount = 0;

    //get the INPUT
    scanf("%d", &n);

    //get n numbers from console 
    //and find the lucky number
    for (i = 0; i < n; i++)
    {
        //get the input
        scanf("%d", &num);

        //if the count of lucky digit in current number more than current lucky number‘s
        if (ndigit(num, 8) > luckyDigCount)
        {
            //set current number as lucky number
            luckyDigCount=ndigit(num,8);    
            luckyNum = num;
        }
    }
    //if lucky number doesn‘t have a lucky digit
    //that means there is no lucky number in this test case
    //so, Print "NO"
    if (luckyDigCount==0)
    {
        printf("NO");
    }
    else
    {
        //Print the lucky number 
        printf("%d\n", luckyNum);
    }
}
/**
 * get the count of lucky digit in the param n
 * @param  n test number
 * @param  k lucky digit
 * @return   the count of lucky digit in the param n 
 */
int ndigit (int n, int k)
{
    int count = 0;
    for (; n; n /= 10)
    {
        if (n%10 == k)
        {
            count++;
        }
    }

    return count;
}

SUMMARY

What if the OUTPUT is the biggest lucky number? Add a judgement statement,that compare current number to the previous lucky number, after we ensure current number is one of the lucky numbers.

An Easy C Program Problem

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原文地址：http://www.cnblogs.com/JacZhu/p/4972880.html