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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 18360 Accepted Submission(s): 8922
算法题做不动 水一道吧
#include<stdio.h>
#include<string.h>
#include<math.h>
int main()
{
int a,b,k,i;
while(scanf("%d%d",&a,&b),a|b)
{
scanf("%d",&k);
int ans=pow(10,k);
if(a%ans==b%ans)
printf("-1\n");
else
printf("%d\n",a+b);
}
return 0;
}
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原文地址：http://www.cnblogs.com/tonghao/p/4982380.html
