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时间:2015-11-22 01:34:39      阅读:184      评论:0      收藏:0      [点我收藏+]

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$\overset{\rightharpoonup }{i},\overset{\rightharpoonup }{j}$

$\frac{s^2}{2}$

$\int \text{Sin}[x] \, dx$

\(\overset{\rightharpoonup }{i}_1\)=\(a_{11}\)\(\overset{\rightharpoonup }{i}_0\)+\(a_{21}\)\(\overset{\rightharpoonup }{j}_0\)+\(a_{31}\)\(\overset{\rightharpoonup
}{k}_0\)

\(\overset{\rightharpoonup }{j}_1\)=\(a_{12}\)\(\overset{\rightharpoonup }{i}_0\)+\(a_{22}\)\(\overset{\rightharpoonup }{j}_0\)+\(a_{32}\)\(\overset{\rightharpoonup

}{k}_0\)

\(\overset{\rightharpoonup }{k}_1\)=\(a_{13}\)\(\overset{\rightharpoonup }{i}_0\)+\(a_{23}\)\(\overset{\rightharpoonup }{j}_0\)+\(a_{33}\)\(\overset{\rightharpoonup

}{k}_0\)

$B=\(\left(
\begin{array}{ccc}
a_{11} & a_{12} & a_{13} \\
a_{21} & a_{22} & a_{23} \\
a_{31} & a_{32} & a_{33} \\
\end{array}
\right)\)$

 

tes

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原文地址:http://www.cnblogs.com/xyzxyzxyzxyzxz/p/4985173.html

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