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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value 3
, the linked list should become 1 -> 2 -> 4
after calling your function.
本题目意思为:仅仅给出一个链表节点,删除这个节点
直接让这个节点等于这个节点的下一个节点即可。
C语言代码如下:
/** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * }; */ void deleteNode(struct ListNode* node) { if(node != NULL) { node->val = node->next->val; node->next = node->next->next; } }
237_Delete Node in a Linked List
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原文地址:http://www.cnblogs.com/Anthony-Wang/p/5001348.html