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Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3, return true.
class Solution { public: bool searchMatrix(vector<vector<int>>& matrix,int r,int c,int target){ if(c<0 || r >= matrix.size()){ return false; } if(matrix[r][c]>target){ return searchMatrix(matrix,r,c-1,target); }else if(matrix[r][c]<target){ return searchMatrix(matrix,r+1,c,target); }else{ return true; } } bool searchMatrix(vector<vector<int>>& matrix, int target) { int m = matrix.size(); if(m==0){ return false; } int n = matrix[0].size(); return searchMatrix(matrix,0,n-1,target); } };
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原文地址：http://www.cnblogs.com/zengzy/p/5005720.html
