标签:codeforces
//area=(n*m)/ ((x+1)*(k-x+1)) //1: x==0; //2: x=n-1 //3: x=m-1 # include <stdio.h> long long max(long long x,long long y) { return x>y?x:y; } int main() { long long n,m,k,sum,t,ans; scanf("%lld%lld%lld",&n,&m,&k); sum=n+m-2; if(k>sum) printf("-1\n"); else if(sum==k) printf("1\n"); else { ans=0; if(n>=k+1)//x=0 { ans=max(ans,m*(n/(k+1))); } else//x=n-1 { t=k-n+2; ans=max(ans,m/t); } if(m>=k+1)//x=0 { ans=max(ans,n*(m/(k+1))); } else//x=m-1 { t=k-m+2; ans=max(ans,n/t); } printf("%lld\n",ans); } return 0; }
Codeforces 450 C. Jzzhu and Chocolate
标签:codeforces
原文地址:http://blog.csdn.net/lp_opai/article/details/37995107