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Given n, generate all structurally unique BST‘s (binary search trees) that store values 1...n.
For example,
Given n = 3, your program should return all 5 unique BST‘s shown below.
1 3 3 2 1 \ / / / \ 3 2 1 1 3 2 / / \ 2 1 2 3
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<TreeNode*> generateTrees(int n) {
if(n<1){
vector<TreeNode *> result;
return result;
}
return help(1,n);
}
vector<TreeNode *> help(int start,int end){
vector<TreeNode *> result;
if(start>end){
result.push_back(NULL);
return result;
}
for(int i=start;i<=end;i++){
vector<TreeNode *> left =help(start,i-1);
vector<TreeNode *> right=help(i+1,end);
for(int j=0;j<left.size();j++){
for(int k=0;k<right.size();k++){
TreeNode *root =new TreeNode(i);
root->left=left[j];
root->right=right[k];
result.push_back(root);
}
}
}
return result;
}
};
95.Unique Binary Search Trees II
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原文地址:http://www.cnblogs.com/zhoudayang/p/5008037.html