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leetcode Remove Invalid Parentheses

时间:2015-12-01 21:16:20      阅读:236      评论:0      收藏:0      [点我收藏+]

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题目连接

https://leetcode.com/problems/remove-invalid-parentheses/ 

Remove Invalid Parentheses

Description

Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results.

Note: The input string may contain letters other than the parentheses ( and ).

Examples:

"()())()" -> ["()()()", "(())()"]
"(a)())()" -> ["(a)()()", "(a())()"]
")(" -> [""]

bfs爆搜。。

class Solution {
public:
	vector<string> removeInvalidParentheses(string s) {
		unordered_map<string, bool> vis;
		ans.clear();
		vector<string> res;
		len = s.length();
		vis[s] = true;
		queue<string> q;
		q.push(s);
		bool find = false;
		while (!q.empty()) {
			string tmp = q.front(); q.pop();
			len = tmp.length();
			if (isOk(tmp)) {
				res.push_back(tmp);
				find = true;
			}
			if (find) continue;
			for (size_t i = 0; i < len; i++) {
				string x = tmp.substr(0, i) + tmp.substr(i + 1);
				if (vis.find(x) == vis.end()) {
					vis[x] = true;
					q.push(x);
				}
			}
		}
		int n, val = -1;
		if (!(n = res.size())) return ans;
		val = res[0].size();
		for (int i = 0; i < n; i++) {
			if (res[i].size() == val) ans.push_back(res[i]);
			else break;
		}
		return ans;
	}
private:
	size_t len;
	vector<string> ans;
	bool isOk(string s) {
		stack<char> q;
		for (size_t i = 0; i < len; i++) {
			if (s[i] == ‘(‘) q.push(‘(‘);
			if (s[i] == ‘)‘) {
				if (!q.empty() && q.top() == ‘(‘) q.pop();
				else q.push(‘)‘);
			}
		}
		return q.empty();
	}
};

leetcode Remove Invalid Parentheses

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原文地址:http://www.cnblogs.com/GadyPu/p/5011171.html

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