LeetCode-- Reverse Linked List II

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/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     public int val;
 *     public ListNode next;
 *     public ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode ReverseBetween(ListNode head, int m, int n) {
        var stack = new Stack<int>();
        var q = new Queue<int>();
        ListNode node = null;
        var c = 1;
		ListNode newNode = null;
        while(head != null)
        {
            if(c >= m && c <=n){
                while(q.Count > 0){
                    var first = MoveNext(ref node , q.Dequeue());
					if(first){
						newNode = node;
					}
                }
                while(c >= m && c<= n){
                    stack.Push(head.val);
                    head = head.next;
                    c++;
                }
				if(head == null){
					 while(stack.Count > 0){
						var first = MoveNext(ref node , stack.Pop());
						if(first){
							newNode = node;
						}
					}
				}
            }
            else{
                while(stack.Count > 0){
                    var first = MoveNext(ref node , stack.Pop());
					if(first){
						newNode = node;
					}
                }
                var f = MoveNext(ref node , head.val);
				if(f)
				{
					newNode = node;
				}
                head = head.next;
				c++;
            }
        }
        
        return newNode;
    }
    
    private bool MoveNext(ref ListNode n , int val){
        if(n == null){
            n = new ListNode(val);
			return true;
        }
        else{
            n.next = new ListNode(val);
            n = n.next;
			return false;
        }
    }
    
}

LeetCode-- Reverse Linked List II

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原文地址：http://blog.csdn.net/lan_liang/article/details/50144827