120.Triangle

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Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.

For example, given the following triangle

[
     [2],
    [3,4],
   [6,5,7],
  [4,1,8,3]
]

The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.

class Solution {
public:
    int minimumTotal(vector<vector<int>>& triangle) {
        int row=triangle.size();
        if(row==0)
            return 0;
        vector<int > temp(triangle[row-1].begin(),triangle[row-1].end());
        for(int i=row-2;i>-1;i--){
            int col=triangle[i].size();
            for(int j=0;j<col;j++){
                temp[j]=min(temp[j],temp[j+1])+triangle[i][j];
            }
        }
        return temp[0];
    }
};

120.Triangle

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原文地址：http://www.cnblogs.com/zhoudayang/p/5013227.html