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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 677 Accepted Submission(s):
358
#include<stdio.h> #include<string.h> #include<stdlib.h> #include<algorithm> #define MAX 100000 #define LL long long using namespace std; LL fun(LL x) { return ((1890*x)%10007+143%10007)%10007; } int main() { int n,m,j,i,k; int s[MAX],a[MAX],b[MAX]; while(scanf("%d",&n)!=EOF) { int sun=0; for(i=1;i<=n;i++) { scanf("%d",&s[i]); a[i]=fun(s[i]);//储存 f(x); b[i]=a[i]-s[i];//储存f(x)和x的差值 sun+=s[i]; } int sum=0; int Max=0; for(i=1;i<=n;i++)//最大子段和代码 { if(sum<=0) sum=b[i]; else sum+=b[i]; Max=max(Max,sum);//求出最大子段 } printf("%d\n",sun+Max); } return 0; }
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原文地址:http://www.cnblogs.com/tonghao/p/5019161.html