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public class Solution { public TreeNode invertTree(TreeNode root) { if (root == null) { return root; } TreeNode tmp1 = root.left; TreeNode tmp2 = root.right; root.right = invertTree(tmp1); root.left = invertTree(tmp2); return root; } }
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原文地址：http://www.cnblogs.com/vision-love-programming/p/5021424.html
