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题目：
Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Write a function to determine if a given target is in the array.
思路：
直接循环一遍查找
package array; public class SearchInRotatedSortedArrayII { public boolean search(int[] nums, int target) { int len; if (nums == null || (len = nums.length) == 0) return false; for (int i = 0; i < len; ++i) if (nums[i]==target) return true; return false; } public static void main(String[] args) { // TODO Auto-generated method stub int[] nums = { 3, 1, 1 }; SearchInRotatedSortedArrayII s = new SearchInRotatedSortedArrayII(); System.out.println(s.search(nums, 3)); } }
LeetCode - Search in Rotated Sorted Array II
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原文地址：http://www.cnblogs.com/shuaiwhu/p/5023079.html
