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1083. List Grades (25)

时间:2015-12-06 13:00:24      阅读:120      评论:0      收藏:0      [点我收藏+]

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Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade‘s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student‘s name and ID, separated by one space. If there is no student‘s grade in that interval, output "NONE" instead.

Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
Sample Output 2:
NONE

 
  1. #pragma warning(disable:4996)
  2. #include <stdio.h>
  3. #include <string>
  4. #include <iostream>
  5. #include <algorithm>
  6. #include <vector>
  7. using namespace std;
  8. struct Stu
  9. {
  10. char name[11];
  11. char id[11];
  12. int grade;
  13. };
  14. vector<Stu> s,s1;
  15. bool cmp(Stu a,Stu b) {
  16. return a.grade > b.grade;
  17. }
  18. int main(void) {
  19. int n;
  20. cin >> n;
  21. for (int i = 0; i < n; i++) {
  22. Stu temp;
  23. scanf("%s %s %d", temp.name, temp.id, &temp.grade);
  24. s.push_back(temp);
  25. }
  26. int low, high;
  27. cin >> low >> high;
  28. for (int i = 0; i < n; i++) {
  29. if (s[i].grade >= low&&s[i].grade <= high) {
  30. s1.push_back(s[i]);
  31. }
  32. }
  33. if (s1.size() == 0) {
  34. cout << "NONE";
  35. return 0;
  36. }
  37. sort(s1.begin(), s1.end(), cmp);
  38. for (int i = 0; i < s1.size(); i++) {
  39. printf("%s %s\n", s1[i].name, s1[i].id);
  40. }
  41. return 0;
  42. }





1083. List Grades (25)

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原文地址:http://www.cnblogs.com/zzandliz/p/5023263.html

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