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题意:训练指南P191
分析:本题特殊,n个物品,n种元素则会爆炸,可以转移到图论里的n个点,连一条边表示u,v元素放在一起,如果不出现环,一定是n点,n-1条边,所以如果两个元素在同一个集合就会爆炸.
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 5; struct DSU { int rt[N], rk[N]; void init(void) { memset (rt, -1, sizeof (rt)); memset (rk, 0, sizeof (rk)); } int Find(int x) { return rt[x] == -1 ? x : rt[x] = Find (rt[x]); } void Union(int x, int y) { x = Find (x); y = Find (y); if (x == y) return ; if (rk[x] > rk[y]) { rt[y] = x; rk[x] += rk[y] + 1; } else { rt[x] = y; rk[y] += rk[x] + 1; } } bool same(int x, int y) { return Find (x) == Find (y); } }dsu; int main(void) { dsu.init (); int ans = 0, x, y; while (scanf ("%d", &x) == 1) { if (x == -1) { printf ("%d\n", ans); dsu.init (); ans = 0; continue; } scanf ("%d", &y); if (dsu.same (x, y)) ans++; else dsu.Union (x, y); } return 0; }
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原文地址:http://www.cnblogs.com/Running-Time/p/5027108.html